There is a number that is 5 times the sum of its digits. What is this number? Answer is not 0.
The number is 45, simply because 45 = 5 * (4 + 5) How does one find this number? Let T be the digit in the tens place and U be the digit in the units place. Then, the number is 10*T + U, and the sum of its digits is T + U. The following equation can be readily written: 10*T + U = 5*(T + U) or 10*T + U = 5*T + 5*U or 5*T = 4*U Thus, T / U = 4 / 5 Since T and U are digits, T must be 4 and U must be 5.